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4 years ago

one number is two more than a second number.twice the first is 4 less than 3 times the second. Find the numbers

Mathematics

1 answer:

Amiraneli [1.4K]4 years ago

7 0

<h3><u>The first number is equal to 10.</u></h3><h3><u>The second number is equal to 8.</u></h3>

x = 2 + y

2x = 3y - 4

Because we have a value of x, we can plug it into the second equation to solve for y.

2(2 + y) = 3y - 4

4 + 2y = 3y - 4

Subtract 2y from both sides.

4 = y - 4

Add 4 to both sides.

8 = y

We can plug this into the original equation to solve for x.

x = 2 + 8

x = 10

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Solve each radical equation. Be sure to check your solutionsa)√(2x-3)=11b)∛(6-x)=-3

leva [86]

Answer:

a) x = 62

b) x = 33

Step-by-step explanation:

Hi there!

a) Let´s write the equation:

√(2x-3) = 11

Square both sides

2x - 3 = 121

add 3 to both sides of the equation

2x = 124

divide by 2 both sides

x = 62

Let´s check:

√(2x-3) = 11

x = 62

√(2(62)-3) = 11

√(124-3) = 11

√121 = 11

11 = 11

x = 62 satisfies the equation

b) Let´s write the equation:

∛(6 - x) = -3

Cube both sides

6 - x = -27

subtract 6 to both sides

-x = -27 - 6

-x = -33

divide by -1 both sides

x = 33

Now, let´s check the result:

∛(6 - x) = -3

x = 33

∛(6 - 33) = -3

∛(-27) = -3

-3 = -3

x = 33 satisfies the equation

8 0

3 years ago

Convert to a fraction show your work 0.56

e-lub [12.9K]

Answer:

14/25

Step-by-step explanation:

14 divided by 25 is .56

3 0

3 years ago

Read 2 more answers

Hours worked / pay

Nadusha1986 [10]

It is c because 8x2=16 and 8x4=32 and so on

7 0

4 years ago

Which type of triangle has side measures of 6 cm, 7 cm, and 12 cm and one angle with a measure of 120°?

Igoryamba

Answer:

scalene and obtuse. All sides are different lengths and it has an angle exceeding 90 degrees

Step-by-step explanation:

3 0

3 years ago

If the substitution u=x/2 is made, the intergal from 2 to 4 1-(x/2)^2/x dx =

stich3 [128]

$\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx$

Setting $u=\dfrac x2$ gives $\mathrm du=\dfrac{\mathrm dx}2$ , or $2\,\mathrm du=\mathrm dx$ . This also makes $2u=x$ .

When $x\to2^+$ , you have $u\to\dfrac22=1$ , while when $x\to4^-$ , you have $u\to\dfrac42=2$ .

Putting everything together, you find that

$\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx=\int_1^2\frac{1-u^2}{2u}(2\,\mathrm du)=\int_1^2\frac{1-u^2}u\,\mathrm du$

which means (B) is the correct answer.

4 0

3 years ago