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lianna [129]
3 years ago
9

Write a program that prompts the user to enter the center and a point on the circle. The program should then output the circle’s

radius, diameter, circumference, and area. Your program must have at least the following functions: distance: This function takes as its parameters four numbers that represent two points in the plane and returns the distance between them.
Computers and Technology
1 answer:
sergij07 [2.7K]3 years ago
4 0

Here is the code in C++.

#include <bits/stdc++.h>

using namespace std;

// function to calculate distance between two points

double distance(int a,int b,int c,int d )

{

 // return the distance between center and point

  return sqrt(pow(c - a, 2) +

               pow(d - b, 2) * 1.0);

}

// driver function

int main()

{

// variables to store coordinates

int x1,y1,x2,y2;

cout<<"Please Enter the center(x y) of the circle: ";

//reading center

cin>>x1>>y1;

cout<<"\nPlease Enter a point(x1 y1) on the circle:";

//reading point

cin>>x2>>y2;

// calling distance() function with 4 parameters

double rad=distance(x1,y1,x2,y2);

// calculating Radius and print

cout<<"Radius of circle is: "<<rad<<endl;

// calculating Diameter and print

cout<<"Diameter of circle is: "<<2*rad<<endl;

// calculating Circumference and print

cout<<"Circumference of circle is: "<<2*3.14*rad<<endl;

// calculating Area and print

cout<<"Area of circle is: "<<3.14*rad*rad<<endl;

return 0;

}

Explanation:

First it will read coordinates of center and point on the circle.The distancebetween center and point on circle is Radius. Call distance() function withfour parameters which are coordinates of center and point. This will return the value of Radius. Diameter is 2 times of Radius.Diameter of a circle is 2*3.14*Radius. and Area of the circle is calculate as 3.14*Radius*Radius. After finding these value print them.

Output:

Please Enter the center(x y) of the circle: 0 0

Please Enter a point(x1 y1) on the circle: 3 4

Radius of circle is: 5

Diameter of circle is: 10

Circumference of circle is: 31.4

Area of circle is: 78.5

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   while (str2[index] != '\0'){

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           retIndex=1;

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       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

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           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

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Answer:

In Python:

year = int(input("Year: "))

if (year % 4) == 0:

  if (year % 100) == 0:

      if (year % 400) == 0:

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      else:

          print("Not a leap year")

  else:

      print("Leap year")

else:

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Explanation:

This line prompts user for year

year = int(input("Year: "))

This condition checks if input year is divisible by 4

if (year % 4) == 0:

If yes, this condition checks if input year is divisible by 100

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If yes, this condition checks if input year is divisible by 400

      if (year % 400) == 0:

If divisible by 4, 100 and 400, then it is a leap year

          print("Leap year")

      else:

If divisible by 4 and 100 but not 400, then it is not a leap year

          print("Not a leap year")

  else:

If divisible by 4 but not 100, then it is a leap year

      print("Leap year")

else:

If it is not divisible by, then it is not a leap year

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Write an if-else statement with multiple branches. If givenYear is 2101 or greater, print "Distant future" (without quotes). Els
kherson [118]

Answer:

// here is code in c.

#include <stdio.h>

// main function

int main()

{

// variable to store year

int year;

printf("enter year:");

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scanf("%d",&year);

// if year>=2101

if(year>=2101)

{

printf("Distant future");

}

//if year in 2001-2100

else if(year>=2001&&year<=2100)

{

   printf("21st century");

}

//if year in 19011-2000

else if(year>=1901&&year<=2000)

{

  printf("20th century");

}

// if year<=1900

else if(year<=1900)

{

  printf("Long ago");  

}

return 0;

}

Explanation:

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Output:

enter year:2018                                                                                                            

21st century

7 0
3 years ago
Read 2 more answers
HELP ME ASAP
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Answer:

1 replies 2 tracking

Explanation:

edge

4 0
3 years ago
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