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Alinara [238K]
3 years ago
10

I’m stuck on this and I need help...

Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

D

Step-by-step explanation:

The ratio of corresponding sides are equal, that is

\frac{4}{8} = \frac{y}{14}

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Simplify negative 5 and 1 over 6 − negative 8 and 1 over 2
Tomtit [17]

Answer:

Hi there!

Your answer is;

17/6 <em><u>OR</u></em> 2 & 5/6

Step-by-step explanation:

(-5+1)/6 - (-8+1)/2

First, simplify in parentheses!

-4/6 - -7/2

Next, change the symbol of 7/2 because two negatives make a positive!

-4/6 +7/2

Next, change the denominators so they both have the same

-4/6 + 7/2

× 3/3

-4/6 + 21/6

Simplify!

17/6

<u>OR</u>

2 & 5/6

Hope this helps

4 0
3 years ago
Charlie's garage has a rectangular floor space. Its length is 3 times its width. Charlie extends the width of his garage to 6 m,
MAXImum [283]

Answer:

The percentage change is 140%

Step-by-step explanation:

Given

L= 3W_1 ---- initial dimension

W_2 = 6m --- new width

A_2 = 45m^2 --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

Area =Length * Width

A_2=L * W_2

Make L the subject

L = \frac{A_2}{ W_2}

Substitute values for A and W

L = \frac{45m^2}{6m}

L = \frac{45m}{6}

L = 7.5m --- this is the length of the garden

Calculate the initial width:

L= 3W_1

Make W1 the subject

W_1 = \frac{1}{3} * L

W_1 = \frac{1}{3} * 7.5

W_1 = 2.5

So, the initial area is:

A_1 = L_1 * W_1

A_1 = 2.5 * 7.5

A_1 = 18.75

The percentage change in area is:

\%A = \frac{A_2 - A_1}{A_1}

\%A = \frac{45 - 18.75}{18.75}

\%A = \frac{26.25}{18.75}

\%A = 1.4

Express as percentage

\%A = 1.4*100\%

\%A = 140\%

4 0
3 years ago
the length of an eastern gray three fog tadpole can be as long as five and twenty two hundredths cenimeters
Setler [38]
The answer would be 5.22
Hope this help :D
5 0
3 years ago
M2-5m-14=0<br>quadratic formula​
Sonja [21]

\bf m^2-5m-14=0 ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{1}m^2\stackrel{\stackrel{b}{\downarrow }}{-5}m\stackrel{\stackrel{c}{\downarrow }}{-14}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ m= \cfrac{ - (-5) \pm \sqrt { (-5)^2 -4(1)(-14)}}{2(1)}\implies m=\cfrac{5\pm\sqrt{25+56}}{2} \\\\\\ m=\cfrac{5\pm\sqrt{81}}{2}\implies m=\cfrac{5\pm 9}{2}\implies m= \begin{cases} 7\\ -2 \end{cases}

3 0
3 years ago
find the x and y-intercepts of the line that passes through the points (-6,-6) (4,-2), I will mark brainliest!!
Monica [59]

Answer:

The x intercept will be (9,0) and the y intercept will be (0,-3.6)

Step-by-step explanation:

If you graph both of these points on the graph you can see the x intercept clearly but you have to solve for the y intercept by plugging it into y=mx+b equation.

5 0
3 years ago
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