What do I do on this problem please help

4. The length of a rectangle is sixteen inches less

-BARSIC- [3]

Answer:

68in

Step-by-step explanation:

l = 3w-16

l-3w = -16

l+w = 96

-4w = -112

w = 28 in

l = 96-28 = 68in

8 0

1 year ago

True or False, An integer divided by its opposite allways equals -1. This is false because of "0" is this correct?

valentinak56 [21]

An integer divided by its opposite always equals -1: this is false. Any number which is not 0 divided by it's opposite is in fact equal to -1, but since 0 is also an integer, it's false. You are right, good job!

4 0

2 years ago

Read 2 more answers

Help, i will give brainliest

andrey2020 [161]

Answer:

The answer is J

Step-by-step explanation:

If you start from Quinn's location (8,7), and move south 3 units, you get to (8,4). Then you move to the west 4 units and that gets you to (4,4).

hope this helped! :)

8 0

3 years ago

URGENT! 40 POINTS! PLEASE HELP!

umka2103 [35]

Answer:

(a) $8 x(5 x-6)=40 x^{2}-48 x$

(c) $\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-21 x+18\end{aligned}$

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation $8 x(5 x-6)$

$8 x(5 x-6)=40 x^{2}-48 x$

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation $-4 x\left(2 x^{2}+1\right)$

$-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x$

Hence, the given statement is false.

(c) To find verify the answer we need to multiplying the equation $(x-3)(5 x-6)$

$\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}$

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation $(2 x+3)\left(x^{2}+3 x-5\right)$

$\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}$

Hence, the given statement is false.

4 0

2 years ago

Read 2 more answers

Find the equation of the circle that satisfies the given conditions. Radius 2 and center (4, -7)?

podryga [215]

$The\ equation\ of\ the\ circle:\\\\(x-a)^2+(y-b)^2=r^2\\\\where\\\\center:(a;\ b)\\\\radius:r$

$Center:(4;-7);\ radius:r=2\\\\(x-4)^2+(y+7)^2=2^2\\\\(x-4)^2+(y+7)^2=4$

6 0

3 years ago