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Ilya [14]
3 years ago
10

A spherical ball just fits inside a cylindrical can,16 centimeters y'all, with a diameter of 16 centimeters. What is the express

ion that give you the volume
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

The correct answer is the expression of the volume of the sphere is \frac{4}{3} ×π× 8^{3} and the expression of the volume of the leftover space is π×8^{3}×16 - \frac{4}{3} ×π× 8^{3}.

Step-by-step explanation:

Height of the given cylindrical can = 16 cms.

Diameter of the given cylindrical can = 16 cms.

Now a spherical ball just fits in this given cylindrical can. Thus the diameter of the ball is equal to the diameter of the can, equal to 16 cms.

Thus the expression of the volume of ball = \frac{4}{3} ×π×r^{3} = \frac{4}{3} ×π× 8^{3}

Expression of the volume of the cylindrical can is π×r^{3}× h = π×8^{3}×16

Expression of the leftover volume would be volume of can minus volume of the ball = π×8^{3}×16 - \frac{4}{3} ×π× 8^{3}.

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Answer:

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The sides of the park measure 30 m and 40 m. They form the sides of a rectangle. The length of the path is along the length and width of the park, so by going along the path, the distance is

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Going through the park, you walk in a straight line from the park to the home along a diagonal of the rectangle. That diagonal is a hypotenuse of a right triangle whose sides measure 30 m and 40 m. We use the Pythagorean theorem to find the length of the diagonal.

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Let the legs of the right triangle be a and b. Let the hypotenuse be c.

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3 years ago
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Step-by-step explanation:

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3 years ago
Can you help me find x?<br> 37% of x is 44.03
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Answer:

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What were the lengths of the legs of a right triangle in which measures 19 degrees and the hypotenuses 15 units long
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Answer:



The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.

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8 0
3 years ago
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