4x^2(7x^3-6x^2+5x-7)

HELP PLEASEEEE. The question is attached. I would appreciate if someone could help me.

Blizzard [7]

a counterclockwise rotation about the origin of 90°

The coordinates of P(3, 3), Q(5, 3), R(5, 7)

The coordinates of P'(- 3, 3 ), Q'(- 3, 5), R'(- 7, 5)

Note that the y-coordinate of the image is the negative of the original, while the x-coordinate of the original becomes the y-coordinate of the image

The rotation which does this is a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x )

8 0

3 years ago

EVALUATE THE FOLLOWING -15 x 6

Nat2105 [25]

the answer is 90

Step-by-step explanation:

I used a calculator so-

6 0

2 years ago

What must be true of PQ?

yulyashka [42]

Interesting question
Usually when you look at something like that construction, you think that AB has been bisected by PQ and that the two segments are perpendicular. They are perpendicular but nowhere is that stated. So the answer is C because all the other answers are wrong.

PQ is congruent AB is not correct. As long as the arcs are equal and meet above and below AB there is no proof of congruency. In your mind widen the compass legs so that they are wider than AB and redraw the arcs. You get a larger PQ, but it has all the original properties of PQ except size.

PQ is not congruent to AQ. How would you prove conguency? You'd have to put both lines into triangles that can be proved congruent. It can't be done.

The two lines are not parallel. They are perpendicular. That can be proven. They meet at right angles to each other (also provable).

8 0

2 years ago

in a proportional relationship the ratio y/x is constant. Show that this ratio is not constant for the equation y=a-14

Colt1911 [192]

To show that the ratio $\frac{y}{x}$ is not constant for the function $y=a-14$ we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here $a$ represents $x$ .

To find the counter examples here, I will use the values $a=20$ and $a=28$ . For $a = 20$ , the equation tells us that the output is

$y=20-14=6$ . For this value of $a$ the point is point is $(20,6)$ . The ratio $\frac{y}{x} =\frac{6}{20}$ . For the $a=28$ , $y=28-14=14$ . For this value of $a$ the point is $(28,14)$ . The ratio $\frac{y}{x} =\frac{14}{28} =\frac{1}{2}$ . Clearly this ratio is not constant for all ordered pairs.