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fiasKO [112]
3 years ago
12

This question is worth 30 points! Look at the image and answer the question.

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0
Idkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
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Complete the statement with &lt;, &gt;, or =.<br><br> 4/7 ___ 1<br><br> &lt;<br> &gt;<br> =
Alex73 [517]
4/7 < 1 because 4/7 is less than 1
8 0
4 years ago
Order the ratios from least to greatest:<br><br> 7:2, 12:4, 20:6, 21:14, 10:5
creativ13 [48]
7:2 least
10:5
12:4
20:6
21:14 greatest
3 0
3 years ago
Read 2 more answers
The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m
larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words=\frac{13!}{4\times 2!\times 3!}=64,864,800

When M's are together . considering 2 M's as one

therefore there are \frac{12!}{3\times 2!\times 3!}=9,979,200

No of ways=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600

(b)No of ways such that M's are separated by at least 2 letters

at least  2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

=45738000

7 0
3 years ago
How many cylindrical can of bottles 12 cm high and with 6 cm diameter could be filled from a tank containing 125 liters of deter
Orlov [11]

Answer:

368 cans.

Step-by-step explanation:

Volume of 1 can = π r^2 h.

Here h (height) = 12 and r (radius) = 1/2 * 6 = 3 cm.

So V =  π * 3^2 * 12

= 108π cm^3.

The tank hold 125 liters

=  125,000 cm^3, so:

Number of cans that could be filled = 125000/ 108 π

= 368.4.

4 0
3 years ago
Read 2 more answers
6. use the distributive property to simplify. -3(x - 10) + x
Roman55 [17]

Answer:

for 6: -2x+30

I dont know for # 8

Step-by-step explanation:

to distribute, you have to multiply -3 by x and -10.

-3(x) - -3(10) + x =

-3x + 30 + x:

then you have to add common terms

-3x + x = -2x

then replace that in your equation to get:

-2x +30

4 0
3 years ago
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