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fgiga [73]
3 years ago
14

How do you solve this?

Mathematics
2 answers:
nikdorinn [45]3 years ago
7 0

Answer:

when i did this we would use wax paper and redraw the shape then rotate it however many degrees but make sure to pin ur pencil to the intersecting point of x and y

Aliun [14]3 years ago
5 0
Hope it helps :)
This is the best i could do

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Can you help me jojuja12
Igoryamba

Answer:Cant read the photo


Step-by-step explanation:


5 0
3 years ago
A wedding cake weighed 8 kg .If of its weight was flour , was sugar, 2 5 ℎ 5 16 ℎ 1 4 ℎ was cream and the rest were nuts ,find t
Dmitriy789 [7]

Answer:

300G

Step-by-step explanation:

Here is the complete question

A wedding cake weighed 8kg. If 2/5th of its weight was flour, 5/16th was sugar,1/4th was cream and the rest were nuts, find the weight of nuts.

fraction of the cake that was nuts = 1 - (2/5 + 5/16 + 1/4)

1 - \frac{32 + 25 + 20}{80} = 3/80

wight of nuts = 3/80 x 8 = 0.3 kg = 300g

5 0
3 years ago
PLEASE HELP AND SHOW WORK WILL MARK BRAINLIEST!!
adelina 88 [10]

Answer:

40 seconds

Step-by-step explanation:

cheetah: y=90x

antalope: y=60x+120

set them = to each other

90x=60x+120

30x=120

x=40

7 0
3 years ago
Plz help need the answer
adell [148]
Time to cry bro !!’
3 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​
UkoKoshka [18]

Answer:

\boxed{m = - \frac{33}{14} }

.

Step-by-step explanation:

Use the form below

\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}

Where

  • m is a slope
  • (x_1,~y_1) and (x_2,~y_2) are the point of the line

.

So, the slope is

(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1

(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}

.

m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }

m = \frac{\frac{11}{2} }{\frac{-7}{3} }

m = \frac{11}{2} \div (-\frac{7}{3} )

m = \frac{11}{2} \times (-\frac{3}{7} )

m = - \frac{33}{14}

.

Happy to help:)

7 0
3 years ago
Read 2 more answers
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