Only numbers possible would be five and zero
V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult
basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9
h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20
v=1/3*64pi*20=1280pi/3 m^3=1350.4
C
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Answer:
see explanation
Step-by-step explanation:
a shift of 3 squares right means add 3 to the x- coordinate
a shift of 1 square down means subtract 1 from the y- coordinate
translation rule is (x, y ) → (x + 3, y - 1 ) , then
(1, 1 ) → (1 + 3, 1 - 1 ) → (4, 0 )
(1, 4 ) → (1 + 3, 4 - 1 ) → (4, 3 )
(3, 1 ) → (3 + 3, 1 - 1 ) → (6, 0 )
Answer:
(5a - [2b - 7c]) and (5a + [2b + 7c])
Step-by-step explanation:
Factor 25a^2 - 4b^2 + 28bc - 49c^2.
Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable. Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:
- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or
-(2b - 7c)^2.
Thus, the original 25a^2 - 4b^2 + 28bc - 49c^2 looks like:
[5a]^2 - [2b - 7c]^2
Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b). Applying this pattern to the problem at hand, we conclude:
Thus, [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])