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earnstyle [38]
3 years ago
10

Which of the following would you classify as workplace violence? A. A co-worker tells you that you’ve got a great body and shoul

d wear tight clothes more often so everyone can appreciate it. B. A customer tries to return a pair of shoes that he has already worn several times. When you tell him company policy prohibits you from refunding his money, he becomes enraged and says, “I know where you live. You’d better give me back my money, or else C. A patron at a restaurant where you work complains that her soup has a hair in it. Coughing and gagging, she flings the bowl at you, burning you with the hot soup as she stomps out the door. D. All of the above E. None of the above
Computers and Technology
2 answers:
aev [14]3 years ago
8 0
I believe it should be C, since it has the most immediate threat to your safety. 
irga5000 [103]3 years ago
6 0
It has to be C because he can't do that to you
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Online Book Merchants offers premium customers 1 free book with every purchase of 5 or more books and offers 2 free books with e
andrey2020 [161]

Answer:

This question has two parts, first part is about programming about a Player class and second for reading string from user and decide how many time duck string entered by user and terminate if user press goose string.

The explanation of both program (executable code) is given below in explanation section.

Explanation:

//Program 1

#include <iostream>

using namespace std;

int main()

{

 bool isPremiumCustomer;

 int nbooksPurchased;

 int totalBookPurchasedWithOffer;

// bool cutomerType;

 int freeBooks;

 cout<<"Press 1 for Premium Customer and 0 for regular Customer";

 cin>>isPremiumCustomer;

 cout<<"How many books you purchased ";

 cin>>nbooksPurchased;

 

 

switch(isPremiumCustomer)// what type of customer is  

{

case 1://if customer is premium

 if (nbooksPurchased >= 5&&nbooksPurchased<8)// purchase book greater between 5 and 8

  {

   freeBooks=1;//offer free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

   

   cout<<"You purchased total book with offer ";//show total books

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 8)//if premium customer purchase more than 8 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;//show total books

    }

  else{

   cout<<"You purchased total book with no offer ";

    cout<<nbooksPurchased;

   }

  break;

case 0:// if customer is regular customer

 if (nbooksPurchased >= 7&&nbooksPurchased<12)//and purchase book between 7 and 12

  {

   freeBooks=1;// offer 1 free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

   cout<<"You purchased total book with offer ";

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 12)//if purchase 12 or more than 12 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;

    }

 else{

  cout<<"You purchased total book with no offer ";

  cout<<nbooksPurchased;

  }

  break;

 

}

 

 

 

return 0;// terminate the program

 

}

/* program 1 has ended

and program 2 is started from here

#######################################################

*/

#include <iostream>

using namespace std;

int main()

{

string readstring;// take input string from user to enter either "goose" or "duck"

int count=0;//count the number of "duck"

while(readstring!="goose")//run loop, until user do not enter string  

{

 cout<<"Enter the string either goose or duck ";// prompt user to enter the string

 cin>> readstring;// read string from user

 if (readstring=="duck")//if string equal to "duck"

 {

  count=count+1;//count number of duck string enter by user

   

 }

}//exit/terminate the loop, if user enter the goose string

cout<< " Number of duck that were read " ;// show how many duck string entered by user

cout<<count;

return 0;// terminate the program

 

}

6 0
3 years ago
if we had a set of 10 constraints and solver had to deterimine which 4 to enforce what would be the binary indicator varibales h
Inessa [10]

Answer:

if we had a set of 10 constraints and solver had to determine which 4 to enforce what would be the binary indicator variables have to  sum to make this happen

answer : 6

Explanation:

number of constraints = 10

solver has to determine which 4 to enforce

Hence the number the Binary indicator will have to sum to enforce 4

will be : (number of constraints) - 4

              = 10 - 4 = 6

5 0
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A half-life is the amount of time it takes for a substance or entity to fall to half its original value. Caffeine has a half-lif
Elena L [17]

Answer:

// here is code in java.

import java.util.*;

class Solution

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // declare variable

         double caffeine;

    // scanner object to read input from user

       Scanner scr=new Scanner(System.in);

       System.out.print("Enter the initial amount of caffeine:");

        // read the initial amount of caffeine

           caffeine=scr.nextDouble();

          // calculate amount of caffeine after 6,12,18 hours

          for(int i=1;i<=3;i++)

          {

               System.out.println("After "+ i*6+" hours:"+(caffeine/2)+" mg");

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               caffeine=caffeine/2;

          }

                 

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create a variable "caffeine" to store the initial amount of caffeine given by user. Run a loop for three time, it will calculate the amount of caffeine left after every 6 hours.First it will give the amount of caffeine left after 6 hours, then caffeine left after 12 hours and in last caffeine after 18 hours.

Output:

Enter the initial amount of caffeine:100

After6 hours:50.0 mg

After12 hours:25.0 mg

After18 hours:12.5 mg

8 0
3 years ago
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