Answer:
y-intercept: (0, 5/2)
x-intercept: (5/3, 0)
Step-by-step explanation:
The y-intercept is found by setting x=0 and dividing by the coefficient of y.
0 +2y = 5
y = 5/2
The x-intercept is found by setting y=0 and dividing by the coefficient of x.
3x +0 = 5
x = 5/3
The intercepts are ...
y-intercept: (0, 5/2)
x-intercept: (5/3, 0)
Let
x = velocity of the water current
t1 = time taken to go downstream
t2 = time taken to go upstream
t1 + t2 = 8
t2 = 8 – t1
v = D/t
Downstream
(4 + x) = 6/ t1
t1 = 6/(4+x)
Upstream
(4 – x) = 6/t2
Substitute expression for t2 to obtain
(4 – x) = 6/ (8-t1)
Substituting the expression of t1 to make a single variable equation, obtaining
6 = (4-x)*(8 – 6/(4+x))
Solving for x,
x= 3.16 m/s
Answer:
Period T of the given function f(x) = sin(2x) + cos(4x)
= π
Step-by-step explanation:
Given that y(x) is a sum of two trigonometric functions. The period T of sin 2x would be (2π÷2) = π. Period T of cos4x would be (2π÷4) that is π/2
Find the LCM of π and π/2 . That would be π. Hence the period of the given function would be π
Answer:
The average mass of one coffee bag is 75kg.
Step-by-step explanation:
The lorry on its own weighs 3500kg.
If it weighs 7250kg alongside coffee bags, we can make the assumption that to find the total mass of the coffee bags, we must take the combined total and subtract the lorry's weight from it.
7250kg subtract 3500kg is 3750kg.
There are 50 coffee bags, so this is the mass of all 50.
If we want to find the mass of one coffee bag, we have to divide the mass of 50 coffee bags by 50.
3750kg divided by 50 is 75kg.
The average mass of one coffee bag is 75kg.
A- 3 and 4 ... hope this helps uu
