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Brums [2.3K]
3 years ago
15

Determine the intercepts of the line X-intercept: (__ , __) Y-intercept: (__, __)

Mathematics
1 answer:
gladu [14]3 years ago
7 0
I’m gonna try to help you. So in the graph the line on the x intercept is between 100 and 150. Meaning it is at 125. The Y intercept line is marked at 275.

Therefore the answer should be
x-intercept: (125, 0)
y-intercept: (0, 275)
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Jessica scores 1825 on the sat. ashley scores 28 on the act assuming that both tests measure the same thing who has the higher s
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<span>With 1026 being the mean score on the SAT and StDev of 209, Jessica has a score of 799/209 z-scores above the mean. Her z-score would be 3.823. The mean of the ACT and StDev are 20.8 and 4.8, respectively. A 28 ACT score would be 7.2/4.8 z-scores above the mean, for a z = 1.500. This means that Jessica has the higher z-score.</span>
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Given the equation p-54-59, which equation is solved for t?
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3 years ago
A cone has a radius of r units and a height of h units. a cylinder has a ridius of 2r units and has the same volume as the cone.
algol [13]
Volume of a cone is calculated as:

V_{cone}= \frac{1}{3} \pi  r^{2} h&#10;

Volume of the cylinder is calculated as:

V_{cylinder}=  \pi R^{2}H

The radius of cylinder is twice the radius of cone. So R=2r. The two volumes are given to be equal, so we can write:

\frac{1}{3}  \pi  r^{2} h= \pi  R^{2} H \\  \\ &#10; \frac{1}{3} r^{2} h= (2r)^{2} H \\  \\ &#10; \frac{1}{3} r^{2} h= 4r^{2} H \\  \\ &#10; \frac{1}{3} h= 4H \\  \\ &#10;H= \frac{1}{12}h 

Thus, the height of the cylinder will be h/12
5 0
4 years ago
Read 2 more answers
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)
Y_Kistochka [10]
We first calculate the expression for (g - f)(x) by subtracting f from g: 6x - (4 - x^2) = x^2 + 6x - 4
Then since we need to calculate the value for x = 3:
(g - f)(3) = 3^2 + 6(3) - 4 = 9 + 18 - 4 = 23
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6 0
4 years ago
37.Where is the incenter of any given triangle ?
Vladimir [108]

Answer:

Part 1) Option The point of concurrency of the angle bisectors of the triangle

Part 2) Option A segment drawn  from a vertex to the midpoint of the opposite side

Step-by-step explanation:

Part 1)

we know that

The <u>incenter</u> is the point where the angle bisectors intersect. The incenter is also the center of the triangle's incircle.

therefore

Is the point of concurrency of the angle bisectors of the triangle

Part 2)

we know that

A <u>median</u> of a triangle is a line segment joining a vertex to the midpoint of the opposite side

therefore

Is a segment drawn  from a vertex to the midpoint of the opposite side

5 0
3 years ago
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