Answer:
sorry I don't understand just trying to get points
The distance the bird has flown by the time Alice and Bob meet is 40 feet.
Given that the distance between Alice and Bob is 1000 feet and their running speed is 10 feet per second and the speed of bird is 20 feet per second.
Distance equals speed multiplied by time.
Distance between Alice and Bob=1000 feet.
Distance between the bird and Bob=1000 feet.
Speed of Alice and Bob=10 feet per second.
The combined speed of Alice and Bob=20 feet per second.
Since the two are running directly toward each other the distance each will cover at the meeting point is 50 feet (1000/20)
The time covered at the meeting point=20 second (1000/50)
Speed of the bird=20 feet per second.
The distance covered by the bird towards Bob at their meeting point is 40 feet(20 feet*20 seconds).
Hence the distance the bird has flown by the time Alice and Bob meet is 40 feet.
Learn more about distance at brainly.com/question/2854969
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Answer: 80°
Step-by-step explanation:
Since, If two secants intersect outside the circle, then the measure of the angle formed is one half of the difference of the measures of the intercepted arcs.
In the given diagram,
Chord VS and chord UT are intersecting externally,
Also, ∠SPT is the angle formed by the intersection of these chords.
Thus, by the above property,
![\frac{1}{2}[m(\widehat{VU})-m(\widehat{ST})]=m\angle SPT](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Cwidehat%7BVU%7D%29-m%28%5Cwidehat%7BST%7D%29%5D%3Dm%5Cangle%20SPT)
![\implies \frac{1}{2}[m(\widehat{VU}) - 20^{\circ}]= 30^{\circ}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Cwidehat%7BVU%7D%29%20-%2020%5E%7B%5Ccirc%7D%5D%3D%2030%5E%7B%5Ccirc%7D)
⇒ Measurement of the arc VU= 80°.
