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4 years ago

Evaluate 3 1/4 + 2 1/3. Select one: a. 12 1/5 b. 5 7/12 c. 5 1/12 d. 7 2/7

Mathematics

2 answers:

seropon [69]4 years ago

4 0

The answer to this question is b. 5 7/12

Svet_ta [14]4 years ago

3 0

Answer:

67/12 or 5 7/12

Step-by-step explanation:

3 1/4=13/4

2 1/3=7/3

----------------

13/4+7/3=39/12+28/12=67/12

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Ivanshal [37]

Answer 1
1/46 = 2/92 = 3/138

Answer 2
x = -7

Answer 3
40

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3 years ago

I will give brainliest to person who answers correctly!

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Answer:

41 is the answer .......

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3 years ago

A line that is perpendicular to 3y=11-8x has slope m=

liberstina [14]

Step-by-step explanation:

for a perpendicular,

make x the subject.

8x=11-3y

x=11/8 +3/8

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x= -1/m

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3 years ago

X - 6y = 4 and 3.x – 18<br> How many solutions

Kobotan [32]

Answer:

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Step-by-step explanation:

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3 years ago

A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate

Shkiper50 [21]

The amount of salt in the tank changes with rate according to

$Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)$

$\implies Q'+\dfrac Q{300+3t}=4$

which is a linear ODE in $Q(t)$ . Multiplying both sides by $(300+3t)^{1/3}$ gives

$(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}$

so that the left side condenses into the derivative of a product,

$\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}$

Integrate both sides and solve for $Q(t)$ to get

$(300+3t)^{1/3}Q=(300+3t)^{4/3}+C$

$\implies Q(t)=300+3t+C(300+3t)^{-1/3}$

Given that $Q(0)=100$ , we find

$100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}$

and we get the particular solution

$Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}$

$\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}$

5 0

3 years ago