Answer:
i think this is the answer
The answer is 78. This is because you change 8 2/3 into a improper fraction which is 26/3. Then do 26/3×9/1. You should cross cancel so cancel out 3 and change it into 1 and change 9 into 3. So now your problem is 26×3=78.
~JZ
Hope it helps.
Here is the required diagram .
![\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(0,3){2}{\line(1,0){4}}\qbezier(0,0)(0,0)(4,3)\qbezier(1,0)(1.2,0.35)(0.8,0.6)\qbezier(3,3)(2.8,2.65)(3.2,2.4)\put(2.5,0.02){\vector(1,0){0}}\put(1.5,3.02){\vector(-1,0){0}}\end{picture}](https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1cm%7D%5Cbegin%7Bpicture%7D%280%2C0%29%5Cthicklines%5Cmultiput%280%2C0%29%280%2C3%29%7B2%7D%7B%5Cline%281%2C0%29%7B4%7D%7D%5Cqbezier%280%2C0%29%280%2C0%29%284%2C3%29%5Cqbezier%281%2C0%29%281.2%2C0.35%29%280.8%2C0.6%29%5Cqbezier%283%2C3%29%282.8%2C2.65%29%283.2%2C2.4%29%5Cput%282.5%2C0.02%29%7B%5Cvector%281%2C0%29%7B0%7D%7D%5Cput%281.5%2C3.02%29%7B%5Cvector%28-1%2C0%29%7B0%7D%7D%5Cend%7Bpicture%7D)
Alternate angles are equal .
<span>=<span><span><span><span><span>(3)</span><span>(x)</span></span>+<span><span>(3)</span><span>(4)</span></span></span>+<span><span>(2)</span><span>(<span>5x</span>)</span></span></span>+<span><span>(2)</span><span>(2)
</span></span></span></span><span>=<span><span><span><span>3x</span>+12</span>+<span>10x</span></span>+<span>4
</span></span></span><span>=<span><span><span><span>3x</span>+12</span>+<span>10x</span></span>+4
</span></span><span>=<span><span>(<span><span>3x</span>+<span>10x</span></span>)</span>+<span>(<span>12+4</span>)
</span></span></span><span>=<span><span>13x</span>+<span>16
Answer = </span></span></span><span>13x</span>+<span>16
(hope this helps)</span>
Answer: -500
Step-by-step explanation:
-408 - 92 = -500