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MArishka [77]
3 years ago
12

A is plotted on a coordinate grid at start bracket 3 and 1 over 2, negative 1 end bracket.. Choose the correct grid that best sh

ows the location of the point. A coordinate grid that shows a point located 4 units to the left and 1 unit down from the origin. A coordinate grid that shows a point located halfway between 3 and 4 units to the right and 1 unit down from the origin. A coordinate grid that shows a point located halfway between 3 and 4 units to the left and 1 unit up from the origin. A coordinate grid that shows a point located halfway between 3 and 4 units to the right and 1 unit up from the origin.
Mathematics
2 answers:
Anvisha [2.4K]3 years ago
6 0
.............................
dalvyx [7]3 years ago
3 0

Answer:

A coordinate grid that shows a point located halfway between 3 and 4 units to the right and 1 unit down from the origin

Step-by-step explanation:

In a coordinate grid, the y axis is plotted on the vertical axis and the x axis is plotted on the horizontal axis. A is plotted on a coordinate grid at (3\frac{1}{2},-1) i.e (\frac{7}{2},-1). Above the origin is the positive y axis, below the origin is the negative y axis, right of the origin is the positive x axis and left of the origin is the negative x axis.

To plot A on the coordinate axis we need to locate 3\frac{1}{2} on the x axis and -1 on the y axis.  3\frac{1}{2} is halfway between 3 and 4, since the x coordinate is positive it is located to the right between 3 and 4 and since the y coordinate is negative it is located 1 unit down from the origin.

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A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs
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Answer:

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Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)

\text{Area of walls and ceiling}=1200+90+120

\text{Area of walls and ceiling}=1410

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,  

\text{ The total painting cost}=10*(\frac{1410}{25})

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Therefore, the total painting cost is $564.  

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