Question

What is the equation of a circle with the center of (2,3) and crosses through the point (2,1)​

Answer 1

Answer:   (x - 2)² + (y - 3)² = 4

Step-by-step explanation:

The equation of a circle is: (x - h)² + (y - k)² = r²    where

• (h, k) is the center of the circle
• r is the radius of the circle.

Given:  (h, k) = (2, 3)  and   (x, y) = (2, 1)

Input those values to find r²:

(x - h)² + (y - k)² = r²

(2 - 2)² + (1 - 3)² = r²

  0       +     4     = r²

                   4    = r²

Now input (h, k) = (2, 3) and r² = 4 into the equation of a circle:

(x - h)² + (y - k)² = r²

(x - 2)² + (y - 3)² = 4