Question

Separate 945 into 3 parts so that the second part is three times the first part and the third part is double the second part. Which of the following equations could be used to solve the problem
A. 945=x+3x+6x
B. 945=x+(x+3)+(x+6)
C. 945=x+9

Answer 1

Answer:

A. 945 = x + 3x + 6x

Step-by-step explanation:

Let x = the first part.

The second part is three times the first part.

So, 3x = the second part.

The third part is three times the second part.

So, 6x = the third part.

The equation is

945 = x + 3x + 6x

Answer 2

Answer:

The correct option is A. 945=x+3x+6x

Step-by-step explanation:

Consider the provided information.  

Separate 945 into 3 parts so that the second part is three times the first part and the third part is double the second part.

Let the first number is x.

The second part is three times the first part = 3x

The third part is double the second part = 2(3x) = 6x

Sum of all the 3 parts is equal to 945.

$945=x+3x+6x$

Hence the correct option is A. 945=x+3x+6x