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sattari [20]
4 years ago
6

Separate 945 into 3 parts so that the second part is three times the first part and the third part is double the second part. Wh

ich of the following equations could be used to solve the problem
A. 945=x+3x+6x
B. 945=x+(x+3)+(x+6)
C. 945=x+9
Mathematics
2 answers:
Oxana [17]4 years ago
6 0

Answer:

A. 945 = x + 3x + 6x

Step-by-step explanation:

Let <em>x = the first part</em>.

The second part is three times the first part.

So, <em>3x = the second part</em>.

The third part is three times the second part.

So, <em>6x = the third part</em>.

The equation is

945 = x + 3x + 6x

sammy [17]4 years ago
6 0

Answer:

The correct option is A. 945=x+3x+6x

Step-by-step explanation:

Consider the provided information.  

Separate 945 into 3 parts so that the second part is three times the first part and the third part is double the second part.

Let the first number is x.

The second part is three times the first part = 3x

The third part is double the second part = 2(3x) = 6x

Sum of all the 3 parts is equal to 945.

945=x+3x+6x

Hence the correct option is A. 945=x+3x+6x

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What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1? y = (StartFraction
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By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is \frac{5y_2+y_1}{6}

<h3>What is section formula ?</h3>

Let point P(x,y) cuts line joining point  A(x_1,y_1) and B(x_2,y_2)  in m_1:m_2 then coordinate of point P is equal to (\frac{m_1x_2+m_2x_1}{m_1+m_2}, \frac{m_1y_2+m_2y_1}{m_1+m_2})

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\frac{5y_2+1y_1}{5+1}\\\\\frac{5y_2+y_1}{6}

By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is \frac{5y_2+y_1}{6}

To learn more about   section formula visit:brainly.com/question/26433769

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