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3 years ago

If a = 2 and b = 3, then what does ab2 equal?

Mathematics

2 answers:

mr_godi [17]3 years ago

5 0

Answer:

Step-by-step explanation:

goblinko [34]3 years ago

4 0

Answer: 12

Step-by-step explanation:

if a = 2, and b =3, then plug them in...

(2)(3)(2)

2 times 3 times 2

2 time 3 = 6, and 6 times 2 = 12

Therefore, the answer is 12.

You might be interested in

What is the y-intercept for f(x) = x2 - 4x +6 ?

never [62]

Answer:

Step-by-step explanation:

the constant is the y-intercept

3 0

3 years ago

Which of the following equations represents the greatest value of x?

Nutka1998 [239]

Solve for x to determine which equation represents the greatest value for x.

Equation 1

$x^2 = 17$

$x$ ≈ $4.12$

Equation 2

$x^2 = 26$

$x$ ≈ $5.1$

Equation 3

$x^3 = 64$

$x=4$

Equation 4

$x^3 = 27$

$x=3$

Answer: Equation 2

7 0

3 years ago

After the booster club sold 40 hotdogs at a football game, it had $90 in profit.

podryga [215]

Step-by-step explanation:

x = goods y = $

x Sold = 40, Y = $90

x Sold = 80, Y = $210

sum of xHotdogs = 40+80 = 120 Hotdogs

Sum of Y$ = $90 + 210 = 300

X = 2A & Y = 3 its mean one hotdogs can sold for one each = $2.25 and we round it to $3

So = XY = 2A + 3

sorry if i wrong

4 0

3 years ago

I found the interval of convergence, but I am not sure how to do the second part, finding the sum of the series as a function of

antiseptic1488 [7]

The given series is geometric with common ratio $6^x - 9$ , which converges if $|6^x - 9|$ (i.e. the interval of convergence). We have the well-known result

$\displaystyle |r| < 1 \implies \sum_{n=0}^\infty ar^n = \frac{a}{1-r}$

If you're not familiar with that result, it's easy to reproduce.

Let $S_N$ be the $N$ -th partial sum of the infinite series,

$\displaystyle S_N = \sum_{n=0}^N \left(6^x - 9\right)^n = 1 + \left(6^x - 9\right) + \left(6^x - 9\right)^2 + \cdots + \left(6^x - 9\right)^N$

Multiply both sides by the ratio.

$\left(6^x - 9\right) S_N = \left(6^x - 9\right) + \left(6^x - 9\right)^2 + \left(6^x - 9\right)^3 + \cdots + \left(6^x - 9\right)^{N+1}$

Subtract this from $S_N$ to eliminate all the powers of the ratio between 0 and $N+1$ .

$\left(1 - \left(6^x - 9\right)\right) S_N = 1 - \left(6^x - 9\right)^{N+1}$

Solve for $S_N$ .

$S_N = \dfrac{1 - \left(6^x - 9\right)^{N+1}}{10-6^x}$

Now as $N\to\infty$ , the exponential term converges to 0 and we're left with

$\displaystyle \sum_{n=0}^\infty \left(6^x-9\right)^n = \lim_{N\to\infty} S_N = \boxed{\frac1{10-6^x}}$

7 0

2 years ago

What is 4h-8h in like terms and terms and identify expression

Andrews [41]

Answer:

Step-by-step explanation:

Expression: 4h-8h=4h

Because both 4h and 8h end in the same variable they can be subtracted when you subtract 4 and 8 you get 4. and You can't forget your variable so you end with 4h

Your expression is a group of terms without an equal sign. 4h and 8h are your terms as well as your answer.

Your expression ends as 4h-8h=4h

3 0

3 years ago