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mash [69]
3 years ago
13

Factor the quadratic expression completely 2x^2-13x+20

Mathematics
2 answers:
aleksley [76]3 years ago
5 0

Answer:

Step-by-step explanation:

2x² - 13x + 20

Sum = -13

Product = 40

Factors=  (-8) ; (-5)

2x² - 13x + 20 = 2x² - 8x - 5x + (-5)*(-4)

= 2x(x - 4) -5(x - 4)

= (x - 4)(2x - 5)

KiRa [710]3 years ago
4 0

Answer:

(2x - 5)(x-4)

Step-by-step explanation:

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The ratio X/Y for the fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z is 10/pY.

<h3>What is a mathematical model?</h3>

A mathematical model is the model which is used to explain the any system, the effect of the components by study and estimate the functions of systems.

Consider a fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z.

The demand for Model Z depends on the gasoline price (q) because customers tend to purchase an electronic vehicle as a substitute for vehicles that run on gasoline when the gasoline price increases.

The demand for Model Z is estimated as

D(p) = 180 + 10q - 4p

Here, <em>p</em> is the price of Model Z.

Consider the following two statements:

  • 1. When the average gasoline price q increases by $1, the revenue-maximizing price p" increases by $X.

D(p) = 180 + 10q - 4p\\D(p) = 180 + 10(q+1) - 4(p+X)

  • 2. When the average gasoline price q increases by $1, the demand at the revenue-maximizing price (i.e., D(p*)) increases by a factor of Y.

D(p)+Y = 180 + 10q - 4p\\(D(p)+Y) = 180 + 10(q+1) - 4(p+X)\\Y= 180 + 10(q+1) - 4(p+X)-D(p)\\

Put the value of demand at the revenue-maximizing price as,

Y= 180 + 10(q+1) - 4(p+X)-(180 + 10q - 4p)\\Y= 180 + 10q+10 - 4p-pX-180 - 10q + 4p\\Y= 10 -pX\\1=\dfrac{10}{Y}-\dfrac{pX}{Y}\\\dfrac{10}{Y}=\dfrac{pX}{Y}\\\dfrac{10}{pY}=\dfrac{X}{Y}

Thus, the ratio X/Y for the fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z is 10/pY.

Learn more about the mathematical model here;

brainly.com/question/4960142

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