The first thing we are going to do is find the equation of motion:
ωf = ωi + αt
θ = ωi*t + 1/2αt^2
Where:
ωf = final angular velocity
ωi = initial angular velocity
α = Angular acceleration
θ = Revolutions.
t = time.
We have then:
ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
ωi = 0
α = 190 rad / s2
Clearing t:
753.60 = 0 + 190*t
t = 753.60 / 190
t = 3.97 s
Then, replacing the time:
θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
θ1 = 1494.51 rad
For (10-3.97) s:
θ2 = ωf * t
θ2 = (753.60 rad / s) * (10-3.97) s
θ2 = 4544,208 rad
Number of final revolutions:
θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
θ1 + θ2 = 961.57 rev
Answer:
the disk has made 961.57 rev 10.0 s after it starts up
I don't know if i understood correctly, but C++ can add numbers by using the + funciton. You could either use:
a = b + c
or
a = a + b
if you want to increment a variable.
If Carly wants to add wind belts for the part of the Atlantic just
south of the equator, she should draw the arrows upward to the left. <span> At the South of the equator are trade winds which blow
wind from the northeast toward the equator. </span>
Answer:
public class Main
{
public static void main(String[] args) {
String[] strs = new String[10];
java.util.Scanner sc = new java.util.Scanner(System.in);
for(int i = 0; i < 10; i++){
System.out.print("Enter string " + (i+1) + ":");
strs[i] = sc.nextLine();
}
System.out.println("The strigs with even number of characters is");
for(int i = 0; i < strs.length;i++){
if(strs[i].length() % 2 == 0){
System.out.println(strs[i]);
}
}
}
}
Explanation:
Answer:
Explanation:
mostTickets=0;
for (k=0; k< ndays; k++){
if (parkingTickets[k]>mostTickets) mostTickets=parkingTickets[k];
}
