1.B - - original function is y = sqrt(x). If we make sqrt(x+4), we will move the original function to the left 4. If we make sqrt(x+4)+3, additionally the original function will be moved up 3.
2.D - original function is y = sqrt(x). If we make sqrt(x-7), we will move the original function to the right 7. If we make 5*sqrt(x-7), additionally the original function will be expanded throw the y-axis.
3.E - original function is y = x^5. If we make -x^5 (multiply x^2 by -1), we will reflect the original function over the x-axis. If we make -x^5 - 4 , we additionally will move the original function down 4.
4.C - original function is y = x^2. If we make (x-3)^2, we will move the original function to the right 3. If we make x^2 - 5 , we will move the original function down 5.
5.A - original function is y = x^2. If we multiply x^2 by 1/3, function will be compressed about the y-axis.
(20x10)+(15x10)= y
the variable is the answer or represents it
(20x10)+(15x10)
20x10=200
+
15x10=150
=
350
no they do not have enough they need 50 more dollars in order to have enough.
I'm assuming that the "linear parent function" is 
. If so:
A. is true.
In fact, the slope of a line written in the form 
is 
, and the line is given by 
C. is true.
Since the origin is the point 
, if we compute the function at 
, we want 
. This is quite trivial since
D. is true.
The domain is affected by denominators (they can be zero), even roots (they don't accept negative inputs) and logarithms (they don't accept non-positive inputs). Since this function has none of these three, the domain is all real numbers.
B. is FALSE.
The range of a function is the set of numbers obtained as output, for all possible inputs. Since, in this case, the input and the output are the same thing, if you give a negative input, you will receive the same negative output. So, the range doesn't consist only of positive numbers.
Error couldn’t find question
First subtract 100-15 to get 85. If 15% is taken off, you would only pay 85% of the original cost.
146.54*.85=124.559
