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pochemuha
3 years ago
13

Determine whether the given procedure results in a binomial distribution​ (or a distribution that can be treated as​ binomial).

If the procedure is not​ binomial, identify at least one requirement that is not satisfied. The YSORT method of gender​ selection, developed by the Genetics​ & IVF​ Institute, was designed to increase the likelihood that a baby will be a boy. When 70 couples use the YSORT method and give birth to 70 ​babies, the genders of the babies are recorded.
Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

Yes, It is an binomial experiment.

Step-by-step explanation:

Consider the provided information.

There are 4 conditions to identify that a distribution is binomial or not.

  1. Binary: That means only two possibility success or failure.
  2. Fixed number of trials.
  3. Independent trials.
  4. The probability of success is constant from trial to trial.

Now consider the provide procedure:

Binary condition is satisfied because baby can be male or not.

Trials are independent because couples were selected randomly. It satisfy the 2nd condition.

There are 70 couples it satisfy the 3rd condition.

Probability of success will be constant as couples selected randomly. It satisfy the 4th condition.

Yes, It is an binomial experiment because procedure satisfies all the criteria for a binomial distribution.

Hence, It is an binomial experiment.

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Question 2 (1 point)
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An equivalent expression would be 12+4x bc u used the distribution property
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4 years ago
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      x - 2y + z = 5   | *2
 ⇒ 2x - 4y+ 2z=10
     3x + 3y - 2z = - 6     } I sum up these relations
--------------------------------
    2x+3x - 4y+3y+2z-2z=10-6
     5x - y = 4       (1)

    3x + 3y - 2z = - 6   | *3         ⇒ 9x + 9y - 6z = - 18
    2x - y + 3z = 11     | *2         ⇒ 4x - 2y + 6z= 22       I sum up these
                                              ----------------------------------
                                                ⇒ 9x+4x+9y-2y-6z+6z= 4
                                                     13x+ 7y= 4     (2)
I write (1) and (2)
5x - y = 4   | *7
35x - 7y= 28
13x+7y=4
48x = 32
x= 32/48=4/6 ( 32:8=4, 48:8=6)
x= 2/3
5x-y=4, 
5*2/3-y=4
y=10/3 -4=10/3-12/3=-2/3
⇒ y= - 2/3
x - 2y + z = 5
2/3 - 2*(-2/3)+z=5
2/3+4/3+z=5
6/3+z=5
2+z=5
z=3
x+y+z=2/3-2/3+3=3

x+y+z=3







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