Answer:
Situational attribution
Explanation:
John is blaming his performance on environmental factors beyond his control. This is <em>situational attribution</em>.
_____
Dispositional attribution would assign the cause to some character trait John has.
Fundamental attribution relates to the way an outside observer assigns causes in the situations they observe. Often, they overemphasize dispositional attribution.
Answer:
--- Radius
--- Height
Explanation:
Given
Object: Can (Cylinder)

Required
Maximize the volume
The surface area is:

Substitute 517.8 for S.A

Divide through by 2

Factorize:

Divide through by 

Make h the subject
--- (1)
Volume (V) is calculated as:

Substitute (1) for h

Open Bracket

Differentiate V

Set V' to 0

Collect Like Terms

Divide through by 3

Divide through by 



Take square root of both sides


Recall that:

Substitute 5.24 for r





Hence, the dimension that maximize the volume is:
--- Radius
--- Height
Answer:
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