Answer:
Lets say that P(n) is true if n is a prime or a product of prime numbers. We want to show that P(n) is true for all n > 1.
The base case is n=2. P(2) is true because 2 is prime.
Now lets use the inductive hypothesis. Lets take a number n > 2, and we will assume that P(k) is true for any integer k such that 1 < k < n. We want to show that P(n) is true. We may assume that n is not prime, otherwise, P(n) would be trivially true. Since n is not prime, there exist positive integers a,b greater than 1 such that a*b = n. Note that 1 < a < n and 1 < b < n, thus P(a) and P(b) are true. Therefore there exists primes p1, ...., pj and pj+1, ..., pl such that
p1*p2*...*pj = a
pj+1*pj+2*...*pl = b
As a result
n = a*b = (p1*......*pj)*(pj+1*....*pl) = p1*....*pj*....pl
Since we could write n as a product of primes, then P(n) is also true. For strong induction, we conclude than P(n) is true for all integers greater than 1.
Option C:
The value of x is 27.
Solution:
Given exterior angles are 56°, 2x°, 85°, 57° and 4x°.
<em>Sum of exterior angles of a polygon = 360°</em>
⇒ 56° + 2x° + 85° + 57° + 4x° = 360°
⇒ 198° + 6x° = 360°
Subtract 198° from both sides of the equation.
⇒ 6x° = 162°
Divide by 6 on both sides, we get
⇒ x° = 27°
⇒ x = 27
The value of x is 27.
Option C is the correct answer.
Cost of milk per carton = $ 70 cents = 70/100 = $0.7
Cost of bread per loaf = $60 cents = 60/100 = $0.6
Cost of cereals per box = $50 cents = 50/100 = $0.5
Cost of meat per pound = $1.50
If x is the number of cartons of milk bought, then
Number of loafs = x/2
Number pf boxes of cereals = x/2 +1
Number of pounds of meat = x/2 +1
Therefore,
0.7*x + 0.6*x/2 + 0.5 (x/2+1) + 1.5 (x/2+1) = 10
0.7x + 0.3x + 0.25x + 0.5 + 0.75x + 1.5 = 10
2x + 2 =10
2x = 8
x = 4
Substituting;
Milk cartons = 4
Number of bread = 4/2 = 2
Boxes of cereals = 2+1 = 3
Pounds of meat = 3
Answer:
5.6
Step-by-step explanation:because if you divide correctly it will equal 5.6
