Question

The sum of two numbers is 50. The first number is 43 less than twice the second number. Write and solve a system of equations to find the two numbers.

Answer 1

Answer: 19 and 31

Step-by-step explanation: Make the first number x, the second number y.

The sum of x and y is 50: x+y=50

x is 43 less than 2y: x=2y-43

replace x in equation x+y=50 with x=2y-43: 2y-43+y=50

combine like terms: 3y-43=50

add 43 to both sides: 3y=93

divide both sides by 3: y=31

replace y in equation x+y=50 with y=31: x+31=50

subtract 43 31 from both sides: x=19

the solution to the question is the first number is 19, the second number is 31