Y = x + 3
to test all of these, just use the visible x-coordinates on the grid and substitute them in the equation.
eg; y = (2) + 3 --> y = 5 . So the line would cross through (2,5)
Answer:
Step-by-step explanation:
6/5×-4=-46
Collecting like terms
6/5x = -46 + 4
6/5x = -42
Multiply each term by 5
6x = -210
Dividing each term by 6
x = -210/6
x = -35
Answer:
We conclude that option A is true as x = 1 is the root of the polynomial.
Step-by-step explanation:
Given the polynomial
Let us determine the root of the polynomial shown below.
switch sides
as
so the equation becomes
Using the zero factor principle
solving
and
The possible roots of the polynomial will be:
Therefore, from the mentioned options, we conclude that option A is true as x = 1 is the root of the polynomial.
S = √2+√8+√18+√32+……………… n terms.
or, S = √2 + 2√2 +3√2 +4√2.+………………….+ n terms.
This is an A.P. in which a = √2. , d = √2.
Sn = n/2.[2.a +(n-1).d].
or, Sn = n/2.[ 2√2 +(n-1).√2].
or, Sn = (n/2).√2.[ 2 +n-1].
or, Sn = n.(n+1)/√2. Answer.
Answer:
2(4x + 1)(x + 1)
Step-by-step explanation:
Given
8x² + 10x + 2 ← factor out 2 from each term
= 2(4x² + 5x + 1)
To factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 4 × 1 = 4 and sum = + 5
The factors are + 1 and + 4
Use these factors to split the x - term
4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )
= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)
= (4x + 1)(x + 1), thus
4x² + 5x + 1 = (4x + 1)(x + 1) and
8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form
