What are some of the best apps for school? Why?

Find the distance between the two points rounding to the nearest tenth

mixas84 [53]

Answer:

8.54

Step-by-step explanation:

formula:

$d=\sqrt{(x2-x1)^2 + (y2-y1)^2}$

$d=\sqrt{(-4 - (-7))^2 + (0-(-8))^2}$

$d=\sqrt{3^2 + 8^2}$

$d=\sqrt{9 + 64}$

$d=\sqrt{73}$

d= 8.54

6 0

3 years ago

Help help plz help help me this is hard

Nikitich [7]

For everyone part of apple juice, there will be 2 orange juice.
If he use 16 part of orange juice. He will need 8 apple juice

8 0

4 years ago

Customer account numbers for a certain company consists of 3 letters followed by 5 numbers how many different account numbers ar

Arturiano [62]

Answer:

1,757,600,000

Step-by-step explanation:

company consists of 3 letters followed by 5 numbers how many different account numbers are possible if repetitions of letters and digits are allowed.

We have 26 lettrs and 10 digits

So, the possible out comes for each one of the letters = 26

And the possible out comes for each one of the numbers = 10

∵ repetitions of letters and digits are allowed.

So, the possible accounts are = 26³ * 10⁵ = <u>1,757,600,000</u>

5 0

4 years ago

Based on a random sample of 25 units of product X, the average weight is 102 lb and the sample standard deviation is 10 lb. We w

Dahasolnce [82]

Answer:

$t=\frac{102-100}{\frac{10}{\sqrt{25}}}=1$

$t_{crit}= 2.49$

Since the calculated value is lower than the critical value we have enough evidence to FAIL to reject the null hypothesis

So then we can conclude that the population mean is not significantly higher than 100

Step-by-step explanation:

Data given and notation

$\bar X=102$ represent the mean score for the sample

$s=10$ represent the standard deviation for the sample

$n=25$ sample size

$\mu_o =100$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is higher than 100, the system of hypothesis would be:

Null hypothesis: $\mu \leq 100$

Alternative hypothesis: $\mu > 100$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

Calculate the critical value

We need to find the degrees of freedom first, given by:

$df= n-1= 25-1 = 24$

Since we are conducting a right tailed test we need to find a critical value on the t distribution with 24 degrees of freedom that accumulates 0.01 of the area on the right and we got:

$t_{crit}= 2.49$

Since the calculated value is lower than the critical value w have enough evidence to FAIL to reject the null hypothesis

So then we can conclude that the population mean is not significantly higher than 100

3 0

3 years ago

A camp counselor is trying to determine, of the places they have previously camped, where his campers' favorite camping spots ar

GarryVolchara [31]

A

B is incorrect, because some of the campers may have never gone camping before, so they would be unable to say which is their favorite camping spot
C is incorrect because all of those campers have never gone camping before, so they would be unable to say which is their favorite camping spot
D is incorrect because she is asking the campers not the counselors

8 0

3 years ago

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