Answer:
13 and 14.
Step-by-step explanation:
So we have two consecutive integers.
Let's call the first integer a.
Since the integers are consecutive, the other integer must be (a+1) (one more than the last one).
We know that the sum of the greatest integer (or a+1) and twice the lesser integer (a) is 40. Therefore, we can write the following equation:

The first term represents the greatest integer. The second term represents 2 times the lesser integer. And together, they equal 40.
Solve for a. Combine like terms:

Subtract 1 from both sides. The 1s on the left cancel:

Divide both sides by 3:

Therefore, a or the first integer is 13.
And the second integer is 14.
And we can check:
14+2(13)=14+26=40
Step-by-step explanation:
1 min = 60 sec
Boxes both can fold per min = 30 + 20 = 50
No of boxes to fold = 200
Time taken in sec = 200 ÷ 50 = 4 min = 60 x 4 = 240 sec
Answer:
1). -98 (integer, real number, rational)
2). 1.98 (real, rational)
3). 1270 (whole, real, integer, rational)
4). 1,232,323 (whole, real, integer, rational)