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AnnZ [28]
3 years ago
14

Write 3.242424... as a mixed number

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0

Answer:

3 8/33

Step-by-step explanation:

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6/3 + - 1/6 Please help guys!
kati45 [8]

Answer:

11/6

Step-by-step explanation:

3 0
4 years ago
If (x+2) is a factor of x^3-6x^2+kx+10, k=
tensa zangetsu [6.8K]
If a polynomial is divisible by x-a, then a is a root of this polynomial.
Here (x-a) is equal to x+2:

x-a=x+2 \\
-a=2 \\
a=-2

So -2 is a root of the polynomial. That means <span>x³-6x²+kx+10</span>=0 for x=-2. Now substitute -2 for x in the equation and solve for k:

(-2)^3-6 \times (-2)^2+ k \times (-2)+10=0 \\&#10;-8-6 \times 4-2k+10=0 \\&#10;-8-24-2k+10=0 \\&#10;-2k-22=0 \\&#10;-2k=22 \\&#10;\boxed{k=-11}
5 0
4 years ago
he vertices of a triangle are P(-3,8), Q(-6,-4), and R(1,1). Name the vertices of the image reflected in the X-axis
klemol [59]

Answer:

P'(-3, -8), Q'(-6, 4), R'(1, -1)

Step-by-step explanation:

When you reflect a point (x, y) across the x-axis, the x-coordinate remains the same, but the y-coordinate gets the opposite sign: it becomes (x, -y).

Thus, if a point P, say, (-3, 8) is eightn units above the x-axis, its reflection P' will be the same distance below, at (-3, -8).

Thus, we get the following transformations.

P (-3, 8)   ⟶ P' (-3, -8)

Q (-6, -4) ⟶ Q' (-6, 4)

R (1, 1)      ⟶ R' (1, -1)

Thus, the vertices of the reflected triangle are P' (-3, -8), Q' (-6, 4), R' (1, -1).

The image below shows ∆PQR and its reflection ∆P'Q'R' across the x-axis.

8 0
4 years ago
25-3u=2u ............????????????????????????
pogonyaev
25 - 3u = 2u

You need to get the variable, u, on one side of the equation. You can do this by adding 3u to both sides.

25 = 5u

Now you want to get u by itself, divide 5 off of both sides to find u.

5 = u
8 0
3 years ago
Read 2 more answers
Given x is less than y compare the following expressions and determine which is greater 2 x - y or 2y - x explain your answer
aleksandrvk [35]
2y-x is greater. x<y therefore 2x < 2y
6 0
3 years ago
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