-12 < -6x
-12/-6 > x divide both sides by -6
12/6 > x two negatives makes a positive
2 > x simplify
x < 2 switch sides
hope this helps, God bless!
Any improper fraction would work for this case since they are all greater than 1. For instance 3/2 * 2 would be equal to 3 which is greater than 2.
We have been given that Judy’s brother Sam has a collection of 96 comic books. We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as 
. Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as 
. Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a <u>total of 10 ways</u> in which Sam can divide his comic books into equal groups.
Our question has been answered.
Answer:
it should be C.188.4
Step-by-step explanation:
i hope it helps :) <3
Answer:
1.56
0.52
Step-by-step explanation:
