Answer:
1280 of the $30 tickets and 600 of the $50 tickets
Explanation:
If x represents the number of $30 tickets and y represents the number if %50 tickets then:
(a) the sum of the tickets sold is 1880 = x + y
(b) how much money is received from the sale of $30 tickets = 30x
(c) how much money is received from the sale of $50 tickets = 50y
(d) the total amount received from the sale is $68,400 = 30x + 50y = $68,400
(e) Solving the simultaneous equations, if 1880 = x + y, then x = 1880 - y. Substitute this in total amount received equation and solve for y i.e. 30(1880 - y) + 50y = $68,400
56,400 - 30y + 50y = $68,400
20y = 12,000
y = 600 tickets (we have to sell 600 of the $50 tickets)
Step 2. Substitute the y figure to get the x amount i.e. 30x + 50(600) = $68,400
30x + 30,000 = $68,400
30x = $38,400
x = 1280 tickets (we have to sell 1280 of the $30 tickets)
