Answer:
2,789ft
Step-by-step explanation:
The set up will give a right angled triangle.
The altitude will be the opposite side = 1600 ft
The angle of depression = 35°
approximate direct distance to the stadium is the hypotenuse of the trisngle= x
Using the SOH trig identity to get the distance
sin 35 = opp/hyp
sin 35 = 1600/x
x = 1600/sin35
x = 1600/0.5736
x = 2,789.4ft
Hence mai’s approximate direct distance to the stadium is 2,789ft
Answer:
7
Step-by-step explanation:
the number = x
8x + 4 = 60
8x = 56
x = 7
The Answer is -69 because if you lay out the problem it is -82+50-37=-69
Answer:
(5,19) lies on the graph of the transformed function y = f(1/5x)
Step-by-step explanation:
Suppose (1,19) is on the graph of y = f (x)
the graph of the transformed function y = f(1/5x)
1/5 is multiplied with x in f(x)
1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5
To make horizontal stretch we change the point
f(x)=f(bx) then (x,y) --->( x/b,y)
We divide the x coordinate by the fraction 1/5
(1,19) ---->
So (5,19) lies on the graph of the transformed function y = f(1/5x)