Let n be the middle number of three consecutive integers. write an expression for the sum of these integers.
2 answers:
The expression for the sum of the three integers is 3n.
If <em>n</em> is the middle number of three consecutive numbers, then the number before <em>n</em> is (<em>n - 1)</em> and the number after <em>n </em> is (<em>n +1). </em>By adding the three terms, we get an expression for its sum:
. Simplifying the expression yields 3n. I hope this helps.
If <em>n</em> is the middle number of three consecutive numbers, then the number before <em>n</em> is (<em>n - 1)</em> and the number after <em>n </em> is (<em>n +1). </em>By adding the three terms, we get an expression for its sum:
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Answer:
<u>There are 17 terms in the sequence</u>
Step-by-step explanation:
<u>Arithmetic Sequence </u>
An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:
Where an is the nth term, a1 is the first term, and r is the common difference.
In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:
We need to express r as an improper or proper fraction:
Substituting:
n=17
There are 17 terms in the sequence