We would factor this
what 2 numbers multiply to get -12 and add to get -4?
-6 and 2
(x-6)(x+2)
the side lengths are (x-6) and (x+2)
First you plot in the y-intercept of the equation. To find the y-intercept, substitute 0 into x. -3m will cancel our giving you y=5. x=0, y=5, the first ordered pair is (0,5). Now after you plot in the y-intercept, use your slope, which is -3, to graph the points of the equation. Starting from (0,5), move down 3 spaces on the y-axis (because it’s -3) and you’ll end up at (0,2). Next move over 1 ( all slopes with just a whole number moves on the x-axis 1 since the whole number divided by 1 doesn’t change the slope number) to the right because it’s a negative linear equation so it’ll go downward. After moving right, you’ll get (1,2). Do a couple more points starting from (1,2) then the 3rd point ABD and so on to get 3 or more points to be able to draw a linear line.
The segment addition postulate tells you that
... JK + KL = JL
a) Filling in the given information, you have
... 3n + (5n-7) = 25
... 8n = 32 . . . . . . . . . . . collect terms, add 7
... n = 4 . . . . . . . . . . . . . divide by 8
b) Now, you know that
... JK = 3n = 3·4 = 12
... KL = 5n-7 = 5·4-7 = 13
The segments are: JK = 12; KL = 13.
The slope of a vertical line is undefined, D.
If you were to try to solve use something like the rise over run method, you would end up with a 0 in the denominator. Since dividing by 0 gives you an undefined result, the slope would be undefined.
Re-write the question like this
6 =
x =
x = 1.565