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astraxan [27]
3 years ago
5

Ian and Danny work for a construction company. The table shows their daily wages (in dollars) for a week picked randomly from th

e calendar year.
lan s wages$: ↔ danny s wages$:
96 \ 153
120 \89
114\91
111\96
106\129
123\94
110\99
Mathematics
1 answer:
Crank3 years ago
5 0

Answer:

a) Mean

b)  Ian earned higher wages than Danny during the days listed

Step-by-step explanation:

Ian and Danny work for a construction company. The table shows their daily wages (in dollars) for a week picked randomly from the calendar year. Ians Wages ()DannysWages() 96 153 120 89 114 91 111 96 106 129 123 94 110 99 The best way to compare Ians and Danny's wages is by using the ______ as the measure of center. Comparing this measure of center of the two data sets indicates that ______ generally earned higher wages during the days listed.

a) The mean also known as average is one of the most common used measure of center of the data. To calculate the mean, you sum all the data and then divide the total sum by the total number of data values.

b) For Ian's wages, the mean (μ) is calculated as:

\mu=\frac{96+120+114+111+106+123+110}{7}=111.43

The mean of Ians wages is $111.43

For Danny's wages, the mean (μ) is calculated as:

\mu=\frac{153+89+91+96+129+94+99}{7}=107.29

The mean of Danny's wages is $107.29

From the two data sets, Ian earned higher wages than Danny during the days listed

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Answer:

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Step-by-step explanation:

The circumference of this circle = 2πr

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3 years ago
A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l
Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

x+0.25x=20,000

1.25x=20,000

\frac{1.25x}{1.25}=\frac{20,000}{1.25}

x=16,000

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

x-0.20x=20,000

0.80x=20,000

\frac{0.80x}{0.80}=\frac{20,000}{0.80}

x=25,000

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be 16,000+25,000=41,000

The total sale price of both cars 20,000+20,000=40,000.

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

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x^2-2x+1=1+1/4

x^2-2x+1=5/4  now the left side is a perfect square...

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x-1=±√(5/4)  add 1 to both sides

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Answer:

D

Step-by-step explanation:

Take it step by step.

The area of a rectangle is width times length.

We know the length is 7 since it's given, and we can find the width by adding shared sides of the square and triangle.

So the width is 10 + 14 or 24

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Finally, the area of the triangle is 1/2 of the base times height and we can find the height by looking at the shared side and using the definition of a rectangle.

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