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3 years ago

I'll give 19 points to whoever answers this question

Mathematics

2 answers:

otez555 [7]3 years ago

5 0

9: I think it is 48
10: 138

valentinak56 [21]3 years ago

3 0

Answer:

for 9 i also got 48

Step-by-step explanation:

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At a grocery store, the price of a watermelon is determined by how many pounds the watermelon weighs. The price of a watermelon

Alexxx [7]

Answer:

$p=0.60w$

Step-by-step explanation:

Let

p ----> the price of a watermelon in dollars

w ---> the weight of a watermelon in pounds

In this problem we have a proportional relationship

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem

$p=kw$

The value of the constant of proportionality k is the same that the unit rate

Find out the unit rate

Divide the total cost by the total weight

$k=\frac{4.38}{7.3}=\$0.60\ per\ pound$

substitute in the equation

$p=0.60w$

7 0

2 years ago

Toni can carry up to 22lb in her backpack,her lunch weighs 1 lb,her gym clothes weighs 3lb and her books (b) 3lb each.how many b

Nadusha1986 [10]

The answer is 6 books

8 0

2 years ago

What is the greatest factor of 52 that is a prime number?

Sophie [7]

<em></em>Factors of 52 = 1, 2, 4, 13, 26, 52.

The greatest factor of 52 that is a prime number is 13.

6 0

2 years ago

How do you graph y+5<6x+2?

kondor19780726 [428]

Answer:

45 should be it

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve Highschool Pre cal

Bezzdna [24]

Option C:

$\ln 64 y^{2}$

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule $a \log b=\log b^{a}$ in the above expression.

⇒ $2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}$

Applying log rule $\log a+\log b=\log (a b)$ in the above expression.

⇒ $\ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)$

We know that $8^{2}=64$

⇒ $\ln \left(8^{2} y^{2}\right)=\ln 64 y^{2}$

Hence, the expression in single natural logarithm is $\ln 64 y^{2}$ .

6 0

2 years ago

I'll give 19 points to whoever answers this question​

I'll give 19 points to whoever answers this question