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Reika [66]
2 years ago
8

For every 24 meals Momoka prepared for customers last night, she prepared 2 meals for employees. Momoka prepared 156 meals. How

many meals did Momoka prepare for customers and for employees last night?
Mathematics
2 answers:
tigry1 [53]2 years ago
7 0

Answer:

<h2>144 meals for costumers and 12 for employees.</h2>

Step-by-step explanation:

If Momoka prepared 156 meals, the major number of meals she prepared for costumers was 144, because if your divide 156 by 24 meals results 6.5, so the nearest number is 6, and 6(24)=144.

Now, if she prepared 144 for costumers, then she prepared only 12 for employees, because that's the difference 156-144=12.

Therefore, Momoka prepared 144 meals for costumers and 12 for employees.

stepan [7]2 years ago
3 0
Momoka made 144 meals for the customers and made 12 meals for the employees, hoped this helps :)
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b)

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\bf \begin{array}{cllll}&#10;\textit{area of a circle}\\\\ &#10;\pi r^2&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{area of a sector of a circle}\\\\&#10;s=\cfrac{\theta r^2\pi }{360}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}&#10;\\\\\\&#10;90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

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