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sergiy2304 [10]
3 years ago
9

Given the exponential equation 3x = 27, what is the logarithmic form of the equation in base 10?

Mathematics
2 answers:
MaRussiya [10]3 years ago
4 0
The correct answer is letter B or the second option

mojhsa [17]3 years ago
3 0

Answer:

The exponential equation is in form of x= log base 10 of 27, all over log base 10 of 3

x=\dfrac{\log_{10}27}{\log_{10}3}

B is correct

Step-by-step explanation:

Given: Exponential equation 3ˣ = 27

We need to write in logarithmic form with base 10

3^x=27

First we will apply log both sides with base 10

\log_{10}3^x=\log_{10}27

x\log_{10}3=\log_{10}27                   \because \log a^m=m\log a    

Now, we will divide by \log_{10}3 both sides

x=\dfrac{\log_{10}27}{\log_{10}3}

Hence, The exponential equation is in form of x= log base 10 of 27, all over log base 10 of 3

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