Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15. Filling in accordingly, we have
. Simplifying a bit gives us
and
. Raising that number inside the parenthesis to the 15th power gives us
. Multiplying to finish means that A(t) = $317.22
50 meters cubed because you have to multiple (2()5)(10)
Using the normal distribution, it is found that:
- 3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
- 3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
- 4 - a) The 25th percentile for the math scores was of 71.6 inches.
- 4 - b) The 75th percentile for the math scores was of 78.4 inches.
<h3>Normal Probability Distribution
</h3>
In a <em>normal distribution </em>with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
Question 3:
- The mean is of 73 inches, hence
.
- The standard deviation is of 3 inches, hence
.
Item a:
The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.
The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
Item b:
The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.
The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
Question 4:
- The mean score is of 75, hence
.
- The standard deviation is of 5, hence
.
Item a:
The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.
The 25th percentile for the math scores was of 71.6 inches.
Item b:
The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.
The 75th percentile for the math scores was of 78.4 inches.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213
Fractions,rats, and percents all interconnect. For ext,50%=11/2 =1:2
Answer:
They have 83 dogs and 50 birds.
There are 133 animals in total in the shelter.
Step-by-step explanation:
So let's call the dogs D and the birds B.
D = 25% + B
What ever the amount of animals, the total for D must always be 25% more than B.
To get 100% of the animals, B must equal 37.5% and D must equal 62.5%.
The way I worked this out was:
100% - 25%= 75%
75% divided by 2= 37.5%
37.5% + 25%= 62.5%
And just to check
37.5% + 62.5% = 100%
So to work out 100%:
37.5% = 50
divide both by 37.5 to get 1%
1% = 1.333333
time both by 62.5 to get 62.5%
62.5% = 83.333313
We'll round that answer because I'm pretty sure they don't have a .333313th of a dog.
So D = 62.5% = 83
They have 83 dogs and 50 birds.
Phew! That was the hard part. Now onto something wayyy easier.
To get the total number of animals in the shelter we just do 83 + 50, which is 133.
There are 133 animals in total in the shelter.
Hope this helps you :)
