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Romashka-Z-Leto [24]
3 years ago
14

Jackson stationery sells cards in packs of 11 and envelopes in packs of 13.If Kina wants the same number of each, how many packs

of cards will she have to buy.
Mathematics
1 answer:
mestny [16]3 years ago
6 0

Answer:

Jackson should buy 13 packs of stationery and 11 packs of envelopes to have same number of each.

Step-by-step explanation:

Stationery is sold in the packs of 11.

Envelopes are sold in the packs of 13.

Now, as 11 and 13 both do not have any other factors than 1 and itself.

⇒ 11 and 13 are PRIME NUMBERS.

Now, 13 =  1 x 13

and  11 =  1 x 11

So, the LCM of the prime numbers 13 and 11  = 13 x 11  = 143  = 11 x 13

So, for 13 packs of Stationery will have 13 x 11  = 143 pieces

and 11 packs of envelopes will have 11 x 13  = 143 pieces

Hence, Jackson should buy 13 packs of stationery and 11 packs of envelopes to have same number of each.

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Thus, 2/3 is the simplified fraction for 12/18 by using the GCD or HCF method. Thus, 2/3 is the simplified fraction for 12/18 by using the prime factorization method.

Step-by-step explanation:

To convert a fraction to a ratio, first write down the numerator, or top number. Second, write a colon. Thirdly, write down the denominator, or bottom number. For example, the fraction 1/6 can be written as the ratio 1:6.

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

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