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sveta [45]
3 years ago
5

Give the name and formula of the compound formed when a Mn2+ cation combines with a (PO4)3- anion. A. Manganese phosphate: Mn3(P

O4)2 B. Magnesium phosphate: Mn2(PO4)3 C. Manganese sulfate: Mn2(PO4)3 D. Magnesium sulfate: Mn3(PO4)2 E. Manganese oxalate: Mn2(PO4)3-
Physics
1 answer:
sergij07 [2.7K]3 years ago
9 0

Answer:

A. Manganese(II) Phosphate Mn3(PO4)2

Explanation: The cation combines with anion through coloumbic forces to form an ionic compound.

The cation combines with anion in the ratio of 3:2 so as to form a neutral and stable compound named as Manganese(II) phosphate.

The IUPAC name of ionic compounds are written as:

First the name of the cation is written with its oxidation state in brackets. Then the name of the anion is written.

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The answer is "60.74^{\circ}".

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Cavity and benzene should be extended in equal quantities.

\to 1.18 \times 10^{-3}\times (1+ \Delta T \times 0.000051) = 1.1\times 10^{-3} \times (1+ \Delta T \times 0.00124)\\\\\to  (\frac{1.18}{1.1})\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 - 1- \Delta T \times 0.00124=0\\\\

\to 0.072+ \Delta T \times 0.000054672 - \Delta T \times 0.00124=0\\\\ \to 0.072+ \Delta T ( 0.000054672 -0.00124)=0\\\\ \to \Delta T ( 0.000054672 -0.00124)= -0.072\\\\ \to \Delta T = -\frac{0.072}{( 0.000054672 -0.00124)}\\\\ \to \Delta T = -\frac{0.072}{-0.001185328 }\\

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