Answer:
c
Explanation:
you need to wait patiently
Based on the Ksp calculations, the molar solubility of AgCl in 0.500 M of NH₃ is equal to 2.77 × 10⁻² M.
<h3>How to determine the molar solubility.</h3>
First of al, we would write the properly balanced chemical equation for this chemical reaction:
AgCl(s) ⇆ Ag⁺(aq)+ Cl⁻(aq) Ksp = 1.8 × 10⁻¹⁰
AgCl(s) + 2NH₃(aq) ⇆ Ag(NH₃)₂⁺(aq) Kf = 1. 7 × 10⁷
<u>Given the following data:</u>
- Ksp of AgCl = 1.8 × 10⁻¹⁰
- Concentration of NH₃ = 0.500
- Kf of ag(nh₃)₂⁺ = 1.7 × 10⁷
K = Ksp × Kf
K = 1. 80 × 10⁻¹⁰ × 1.7 × 10⁷
K = 3.06 × 10⁻³
Mathematically, the Ksp for the above chemical reaction is given by:
![K=\frac{ [Ag(NH_3)_2^{+}][Cl]}{[NH_3]^2}\\\\3.06 \times 10^{-3}=\frac{[x][x]}{0.50^{2 }}\\\\3.06 \times 10^{-3}=\frac{x^2}{0.25}\\\\x^2 = 7.65\times 10^{-4}\\\\x=\sqrt{7.65\times 10^{-4}}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%20%5BAg%28NH_3%29_2%5E%7B%2B%7D%5D%5BCl%5D%7D%7B%5BNH_3%5D%5E2%7D%5C%5C%5C%5C3.06%20%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B0.50%5E%7B2%20%7D%7D%5C%5C%5C%5C3.06%20%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7Bx%5E2%7D%7B0.25%7D%5C%5C%5C%5Cx%5E2%20%3D%207.65%5Ctimes%2010%5E%7B-4%7D%5C%5C%5C%5Cx%3D%5Csqrt%7B7.65%5Ctimes%2010%5E%7B-4%7D%7D)
x = 2.77 × 10⁻² M.
Read more on molar solubility here: brainly.com/question/3006391
There are all examples of: A. body language.
Mainly, the mass of a planet doesn't matter, considering many planets are made up of gas, and how in different situations, atmospheres can be destroyed (The Sunburnt off Mercury's Atmosphere). However, in some cases, the planet can be in a good situation on the galactic map and have great conditions for an atmosphere, such as Earth. In which case, the mass of an object can attract a smaller object, causing gravity. Therefore, the bigger the mass of a planet when in right and specific conditions, the more atmosphere it can attract, if there is any floating by the planet.
If it is bigger it will have more gravitational influence and therefore gather more gases.
The technique to improve internal validity is D) Addition of a control group.
<h3>What is
internal validity?</h3>
Internal validity serves as the study which bring about the establishment of a trustworthy cause-and-effect relationship that can be found in treatment and an outcome.
it should be noted that Internal validity also helps to eliminate alternative explanations , hence, The technique to improve internal validity is D) Addition of a control group.
Learn more about internal validity on:
brainly.com/question/968894
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COMPLETE QUESTOIN:
Which of the following is a technique to improve internal validity ____________?
A) Experimenter expectancy
B) Participant bias
C) Use of a confederate
D) Addition of a control group
