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yulyashka [42]
4 years ago
5

Parabola,Can someone please help me please ?

Mathematics
1 answer:
ivanzaharov [21]4 years ago
4 0

Answer:

a. opens: downward

b. vertex: (4, 2)

c. x-intercepts: (2, 0), (6, 0); y-intercept: (0, -6)

d. a.o.s.: x = 4

Step-by-step explanation:

<h3><u>A:</u></h3>

Based on the picture the parabola opens downwards. Right away you know that the "a" value in the parabola's equation will be negative.

<h3><u>B:</u></h3>

To find the coordinates of the vertex, you'll need to look at the picture. Remember: look on the x-axis first and then the y-axis next.

The very top of the parabola (maximum point = vertex) is at the x-value of 4 and the y-value of 2. This means the coordinates of the vertex of this parabola is (4, 2).

<h3><u>C:</u></h3>

To find the x-intercepts, look at the x-axis and see where the parabola crosses it. The parabola goes through the x-axis at the x-values of 2 and 6, so the x-intercepts of this parabola are (2, 0) and (6, 0).

To find the y-intercept, look at the y-axis and see where the parabola crosses it. The parabola intersects the y-axis at the y-value of -6, so (0, -6) would be the y-intercept.

<h3><u>D:</u></h3>

The equation for the axis of symmetry of a graph is always x = h, where h is the x-value of the coordinate of the vertex.

Since the vertex is (4, 2), where 4 = h, the equation of the axis of symmetry would be x = 4.

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