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Elis [28]
3 years ago
15

The area of a square is tripled by adding 10 cm to one dimension and 12 cm to the other. Determine the side length of the square

.
Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0
Area = length *width
A = x²
3x² = (x+10)(x+12)
3x² = x²+10x+12x+120
3x² = x²+22x+120
3x²-3x² = x²+22x+120-3x²
0 = -2x²+22x+120
Factor to solve for x: 
-2(x²-11x-60)
(x+4)(x-15)
x = -4  & x = 15 but we can't have a negative length so we eliminate 4. The length of the square is 15 cm.
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30 PTS <br> Please make sure its easy to understand
arlik [135]
1. -1/20
work: Write all numerators above the least common denominator: -8+2+5/20
*Calculate the sum or difference: -1/20
4 0
3 years ago
A helicopter flying at an altitude of 600 ft dropped a package to a lifeboat. Use the formula t= - to find how many
Andre45 [30]

Answer:

6.1 seconds

Step-by-step explanation:

<u><em>The correct question is</em></u>

A helicopter flying at an altitude of 600 ft dropped a package to a lifeboat. Use the formula t= √h/4 to find how many  seconds it takes for the package to reach the lifeboat. Round your answer to the nearest tenth of a second

we have

t= \frac{\sqrt{h}}{4}

substitute the value of h in the formula

h=600\ ft

t= \frac{\sqrt{600}}{4}=6.1\ sec

8 0
3 years ago
What is the soultion to the linear system y=2x and y=x+4
uranmaximum [27]

Answer:

x = 4; y = 8

Step-by-step explanation:

y=2x

y=x+4

2x = x + 4

x = 4

y = 2x = 2(4)

y = 8

Solution: x = 4; y = 8

5 0
2 years ago
Four more than twice Kai’s age does not equal Kara’s age. If Kara is 15 years old, find Kai’s age. Let k = Kai's age.
Cloud [144]
Just -4 to 15 and the divide
7 0
3 years ago
Read 2 more answers
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
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