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3 years ago

Help me asap please!

Mathematics

1 answer:

sveta [45]3 years ago

4 0

Answer:

Earths moon:

Scientific: 7.35x10^22

Standard:73500000000000000000000

for the rest im only going to give you the scientific method

Mercury: 3.205x10^23

Venus 4.867x10^24

Jupiter 1.898x10^27

Saturn 5.683x10^26

Uranus 8.681x10^25

Neptune 1.024x10^26

Phobos 10.6x10^15

Ariel 1.27x10^21

Titan 1.3452x10^23

I hope this helps

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Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

3 years ago

Angelica colored in 0.60 of the squares on her grid. What is the expression 0.60 as tenth in fraction

xz_007 [3.2K]

If I understand the question correctly, 6/10.

8 0

3 years ago

Does anyone know this and if it is extraneous or not?

Anna11 [10]

Addd 4 to both sides
$\sqrt{x+9}=5$
sqare both sides
x+9=25
minus 9 both sides
x=16

plug it in for x and see
$\sqrt{16+9}-4=1$
$\sqrt{25}-4=1$
$5-4=1$
1=1
true

not extraneous
an extraneous root would be x=-34

5 0

3 years ago

Find the prime factorization of 72.

barxatty [35]

Answer:

2^3×3^2

and yh

Step-by-step explanation:

2×2×2×3×3

5 0

3 years ago

Read 2 more answers

The slope field for the differential equation dy/dx=(3y)/(xy+5x) will have vertical segments when

Inessa05 [86]

Answer:

E) x=0 or y=-5

Step-by-step explanation:

The slope field will have vertical segments when dy/dx is undefined, that is, dy/dx is a division by 0.

We have that

dy/dx=(3y)/(xy+5x)

So the slope field will have vertical segments when

$xy + 5x = 0$

$x(y + 5) = 0$

This is when x = 0 or y = -5.

So the correct answer is:

E) x=0 or y=-5

3 0

3 years ago