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2 years ago

Help me asap please!

Mathematics

1 answer:

sveta [45]2 years ago

4 0

Answer:

Earths moon:

Scientific: 7.35x10^22

Standard:73500000000000000000000

for the rest im only going to give you the scientific method

Mercury: 3.205x10^23

Venus 4.867x10^24

Jupiter 1.898x10^27

Saturn 5.683x10^26

Uranus 8.681x10^25

Neptune 1.024x10^26

Phobos 10.6x10^15

Ariel 1.27x10^21

Titan 1.3452x10^23

I hope this helps

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in the last election, 1,200 people in the precinct voted. the ratio of men to omen was 3 to 5. how many of the voters were women

AysviL [449]

3+5=8

1200 voters

1200/8 = 150

Female: 5 x 150 = 750 voters

Male: 3 x 150 = 450 voters

8 0

2 years ago

Omar grouped the terms and factored the GCF out of the groups of the polynomial 3x3 – 15x2 – 4x + 20. His work is shown.

Phoenix [80]

Answer:

2nd option

Step-by-step explanation:

Given

3x³ - 15x² - 4x + 20

step 1 ( group the first/second and third/fourth terms )

(3x³ - 15x² ) + (- 4x + 20)

step 2 ( factor each group )

3x² (x - 5) - 4(x - 5) ← note factor of - 4 ( not + 4 )

step 3 ( factor out (x - 5) from each term )

(x - 5)(3x² - 4)

4 0

2 years ago

Read 2 more answers

I will mark brainlest <br><br> What is (-5) - (-98)<br><br> lol I am just doing this for fun

denpristay [2]

Step-by-step explanation:

$( - 5) - ( - 98) \\ ( - 5) + 98 = 93$

6 0

2 years ago

Read 2 more answers

Triangle ABC and Triangle DEF are similar. Find the unknown measures. (t = ? and u = ?)

Marianna [84]

T= 60°

It is an equilateral triangle which means all sides and angles are equal

u= 10m

It is an equilateral triangle which means all sides and angles are the same

4 0

2 years ago

6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0

2 years ago