Question

0 = (2y - 1)(8 - y)

Answer 1

I'll teach you how to solve 0 = (2y - 1)(8 - y)

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0 = (2y - 1)(8 - y)

Switch sides:

(2u-1)(8-d)=0

Using the zero factor principle:

Solve 2u-1=0:

Add 1 to both sides:

2u-1+1=0+1

Simplify:

2u=1

Divide both sides by 2:

2u/2=1/2

Simplify:

u= 1/2

Solve 8-d=0:

Subtract 8 from both sides:

8-d-8=0-8

Simplify:

-d=-8

Divide both sides by -1:

-d/-1= -8/-1

Simplify:

d=8

Your Answers Are u= 1/2, d=8

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