What is the most reasonable interval and how do you find it I. This set of numbers 125, 200, 150, 75,275, and 300
1 answer:
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Okay, so first of all, if the trapezoid was translated right 4,
Then all the (x)'s should be 4 more than the original value
For example: (2,-3) <span>→ (6,-3)
Now since the Trapezoid was translated down 3,
Then all the (y)'s should be 3 less than the original value
For example: (2,-3) </span><span>→ (2,-6)
Now do this to all the Vertices
</span>
Final Answer: <span>Option 2</span>
Then all the (x)'s should be 4 more than the original value
For example: (2,-3) <span>→ (6,-3)
Now since the Trapezoid was translated down 3,
Then all the (y)'s should be 3 less than the original value
For example: (2,-3) </span><span>→ (2,-6)
Now do this to all the Vertices
</span>
Final Answer: <span>Option 2</span>
area formula is
where:
b1 = small base
b2 = large base
h = height
then solve:
asnwer: 12 square units
