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aivan3 [116]
3 years ago
14

Y ≤ -4(x – 13) – 2 when y = 38?

Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

hear you go

Step-by-step explanation:

y\leq-4(x-13)-2

38\leq-4x+52

x\geq-3.5

:)

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Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

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substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

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Part 2) Find the perimeter

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C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

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AC=12\sqrt{2}\ cm

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P=(6\pi+12\sqrt{2})\ cm

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P=6(\pi+2\sqrt{2})\ cm

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