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wolverine [178]
3 years ago
11

What is the value of x when x^2=0.008

Mathematics
1 answer:
stellarik [79]3 years ago
6 0
First you need to get rid of the power of 2 by square rooting both sides. And that is it. The answer is: 0.089
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A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the recta
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#1
A= \sqrt[3]{81}*3^{ \frac{2}{3} }= \sqrt[3]{3^4}*3^{ \frac{2}{3} } = 3^{ \frac{4}{3} }*3^{ \frac{2}{3} }=3^{ \frac{4}{3} + \frac{2}{3} }=3^2=9

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#2
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8 0
4 years ago
Help ASAP please!! Thank you!!
Lady_Fox [76]

Solution for the system of linear equations is (4, - 3)

<u>Step-by-step explanation:</u>

Step 1:

Given system of equations

x - 3y = 13 -------- (1)

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Step 2:

Multiply eq(2) with 2 to make coefficients of x equal.

2x - 6y = 26 ------ (3)

Step 3:

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Step 4:

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Step-by-step explanation:

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Step-by-step explanation:

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