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Law Incorporation [45]
4 years ago
6

F(x)=-5x

Mathematics
1 answer:
qaws [65]4 years ago
4 0

Answer:

D

Step-by-step explanation:

(f×g)(x)=-5x(8x^2-5x-9)=-5x(8x^2)-5x(-5x)-5x (-9)=-40x^3+25x^2+45x

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7 0
3 years ago
What is the answer to the equation 7/9+1/7+3/5
Eva8 [605]

Answer:

Step-by-step explanation:

1.52063492063

3 0
4 years ago
Read 2 more answers
Now write 12% as a fraction in simplest
Rama09 [41]
Answer: 3/25


Explanation:
12% as a fraction is 12/100. 12/100 divided by 4 is 3/25.

Hope this helped <3
5 0
3 years ago
Read 2 more answers
Ron works at the local bookstore for an hour every day. He earns $5 daily from this job. If he adds this amount to his daily all
eimsori [14]
$5

The equation is true when we plug 5 in for x. So, x=5 and therefore Ron’s daily allowance is $5.

7(5+5) = 70
7(10) = 70
70 = 70 ✔️

7(10+5) = 70
7(15) = 70
105 = 70 ❌

7(15+5) = 70
7(20) = 70
140 = 70 ❌

7(20+5) = 70
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8 0
2 years ago
What are the amplitude, period, and midline of f(x)=-4 cos (2x-n)+3?
tangare [24]
To find the amplitude and period you need to be familiar with the following equation. Also you need to know that the standard cos has a period of 2\pi and the midline is a line that runs between the max and min of the y-values of the function.

Equations:
f(x) = A cos(Bx +C) + D
f(x) = -4 cos(2x -n) + 3

A = amplitude = |-4| = 4
B = 2
C = phase shift = n = 0 
D = vertical shift = midline = 3

Amplitude = 4

Find the period:
Period = \frac{2\pi}{B} = \frac{2\pi}{2} = \pi

Find the midline:
We know that the amplitude is 4  so we have a range from -4 to 4. The standard y = cos(x) has its midline at 0 so y = 0. This is also true for y = -4 cos(x). In your equation though, you have a vertical shift of +3 so this changes our midline. With an amplitude of 4, which gives us a range from -4 to 4(our y-values), the shift moves this up by 3 so that means we will have new y-values and a range of -1 to 7. Now we need to find the midline(the middle of our y-values) of our new range. We can find this by using the following formula
Midline = \frac{Y_1 + Y_2}{2} = \frac{-1+ 7}{2} = \frac{6}{2} = 3

Midline:
y = 3

Note, in the following equations that D = 3 = midline

y = A (Bx+C) + D
y = -4 (2x + n) + 3

Also, the picture that is attached is what your equation looks like when graphed.


7 0
4 years ago
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