The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
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Answer:
6 pounds 3 ounces
Step-by-step explanation:
16 oz in a lb. 16 *6 = 96. Leaving 3 oz left.
Answer:
450 people paid the discounted fare and 750 people paid the regular fare.
Step-by-step explanation:
let r be regular fares paid and d be discounted fares paid
Total fares = 0.8r + 0.4d = 780
Since 1200 people paid the fares,
r + d = 1200 = Total people
Rearrange this formula:
r = 1200 - d
Substitute r into Total Fares formula
Total fares = 0.8r + 0.4d
780 = 0.8(1200-d) + 0.4d
780 = 960 - 0.8d + 0.4d
780 = 960 - 0.4d
0.4d = 180
d = 450
Sub d=450 into Total people formula
r + d = 1200 = Total people
r + 450 = 1200
r = 1200-450
r = 750
450 people paid the discounted fare and 750 people paid the regular fare.
Answer:
x = 185.458 ft
Step-by-step explanation:
When we draw a picture, we are able to see that we need to use sin∅ to solve this problem:
sin15° = 48/x
xsin15° = 48
x = 48/sin14°
737 people I’m pretty sure